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# Solving Systems of Equations - Two Lines

It is important to note that some equations have decimals or fractions as coefficients. Systems do not always have nice integers in the solutions

Example 1: When the equations have fraction coefficients we must multiply each equation by its LCM to obtain integral coefficients. and  find Now we must multiply each equation so that one of the variables has coefficients that are â€œequal and oppositeâ€. now find Add the equations then simplify to get x = 56

Replace x = 56 in the equation: 7(56) − 6y = 2

392 − 6y = 2 Add opps: - 6y = - 390

multiply recip: to find y = 65

Check the values in both equations The solution point: { (56, 65) }

Add two equations in a system of equations, and obtain another equation in the system (having the same solution). Also multiply an equation by a real number and obtain another equation in the system, and combine the two processes.

The object in the Addition Method is to add two of the equations in order to eliminate one of the variables. The resulting equation can then be solved for either x = h or y = k and which can then be used as a replacement in one of the given equations to find the value of the other one.

Example 2: Multiply the first equation by -4 Now add and get This gives Replace in the first equation: Check the values in both equations The solution point: Example 3: (1) See that the LCM of the 1st equation is 12 and of the 2nd is 6.

(2) Multiply each by the LCMâ€™s (3) Now solve the simplified system --. To get equal and opposites multiply the 1st by 2 and the 2nd by +3 then add the results: Replace x = 2 in (3): 4(2) + 3y = 14 which yields y = 2

Go back to the original equations and substitute both: 